Question

Divide 420 into two parts such that one sixth of one part may exceed the one third of the other part by 10​

Answer 1

Answer:

300 and 120

Step-by-step explanation:

let one number is X then another number will 420-X.

according to the question,

1/6×X ={1/3×(420-X)}+10

=>X/6={(420-X)/3}+10

=>X/6=(420-X+30)/3

=>X/6=(450-X)/3

=>(X/6)×3=450-X

=>X/2=450-X

=>X=2(450-X)

=>X=900-2X

=>X+2X=900

=>3X=900

=>X=300

ANOTHER NUMBER IS 420-X=420-300=120

HENCE, THE NUMBERS ARE 300 AND 120

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