Math, asked by shubhamphad, 6 months ago

Divide 44 (y4

– 5y3

– 24y2

) by 11y (y – 8 ).​

Answers

Answered by gopalpvr
5

Answer:

4y(y+3)

Step-by-step explanation:

Divide 44 (y4– 5y3– 24y2) by 11y (y – 8 ).

= 44y2( (y2– 5y– 24) ÷ 11y (y – 8 ).

= 44y2( (y2– 5y– 24) ÷ 11y (y – 8 ).

= 44y2( (y– 8)(y + 3) ÷ 11y (y – 8 ).

= 4y(y+3)

Answered by rekhakhandal469
1

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Step-by-step explanation:

Divide 44 (y4– 5y3– 24y2) by 11y (y – 8 ). = 44y2( (y2– 5y– 24) ÷ 11y (y – 8 ). = 44y2( (y2– 5y– 24) ÷ 11y (y – 8 ).

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