Question

divide 45 into two parts such that six times the smaller part is 6 more than five times the greater part. I need it for 8th std level

Answer 1

Answer:

24 and 21

Step-by-step explanation:

let the larger number be x

smaller number be y

x + y = 45

x = 45 - y

six times the smaller number is 6 more than five times the larger number

5x + 6 = 6y

5x - 6y = -6

5(45 - y) - 6y = -6

225 - 5y - 6y = - 6

225 - 11y = - 6

- 11y = - 6 - 225

- 11y = - 231

11y = 231

y = 231/11

y = 21

x = 45 - y

x = 45 - 21

x = 24

therefore the numbers are 24 and 21

hope you get your answer