Question

divide 4500 in 2 part such
that 5% of the first part is equal to the 10% of the second part

Answer 1

Answer:

Step-by-step explanation:

let the numbers be x and 4500-x

5x/100 = 10/100[4500-x]

x/20 = 450 - x/10

x/20 + x/10 = 450

3x/20 = 450

x = 3000

4500-x = 4500-3000 = 1500

the numbers are 3000 and 1500

Answer 2

Answer:

Step-by-step explanation:

Let x and y be two divided parts of 4500, then ;

x+y = 4500

x = 4500-y

(5/100)x = (10/100)y

x/20 = y/10

10x = 20y

x = 2y

comparing both equation we get ;

2y = 4500-y

3y = 4500

y = 1500

x = 2×1500

= 3000

hence the 4500 is been divided into two parts of 1500 & 3000