Question

divide 4500 into two parts such that 5% of the first part is equal to 10% of the second part ​

Answer 1

Answer:let x and y be two divided parts of 4500, then ;

x+y = 4500

x = 4500-y

(5/100)x = (10/100)y

x/20 = y/10

10x = 20y

x = 2y

comparing both equation we get ;

2y = 4500-y

3y = 4500

y = 1500

x = 2×1500

= 3000

hence the 4500 is been divided into two parts of 1500 & 3000.

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Answer 2

Answer:

suppose x and y are two divided

parts of 4500. then

x+y=4500 __ (1)

given

5% of x = 10% of y

100

5x

​

=  

100

10y

​

 

x=2y

2y+y=4500

3y=4500

y=1500

x+1500=4500

x=4500−1500

x=3000

hence the 4500 is been divided into  

two parts of 1500 and 3000.