Question

divide 4500 into two parts such that 5% of the first part is equal to 10% of the second part...

Answer 1

Lat the parts be a and b

According to question

a+b = 4500
a= 4500 - b

5% of a = 10% of b
=> 5a/100 = 10b/100
=> 5a = 10b
=> a= 2b
=> 4500 - b = 2b
=> 4500 = 3b

b = 1500
a = 3000

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Assumption

First Part = p

Second Part = n

Now here,

Given,

$\tt{\rightarrow\dfrac{5}{100}p=\dfrac{10}{100}n}$

Further,

$\tt{\rightarrow n=\dfrac{5}{100}p\times\dfrac{100}{10}}$

$\tt{\rightarrow n=\dfrac{5}{10}p}$

$\tt{\rightarrow n=\dfrac{1}{2}p}$

Now,

Putting value of n

$\tt{\rightarrow p+\dfrac{p}{2}=4500}$

$\tt{\rightarrow\dfrac{2p+p}{2}=4500}$

3p = 4500 × 2

3p = 9000

$\tt{\rightarrow p=\dfrac{9000}{3}}$

p = 3000

Now,

$\tt{\rightarrow n=\dfrac{1}{2}p}$

$\tt{\rightarrow n=\dfrac{1}{2}\times 3000}$

= 1500

Hence,

First Part = 3000 , Second Part = 1500