Math, asked by Praneethworld, 1 year ago

Divide ₹47 among A,B and C so that A may have ₹10 more than B and B has ₹8 more than C.
Please show calculation.

Answers

Answered by AnanyaSrivastava999
3
total money = 47
let the money C has = x
money B has = x+8
money A has = x+8+10 =x+18

so we have an equation
x+x+x+8+18=47
3x+26=47
3x= 21
x= 7

x=7
x+8=7+8=15
x+18=7+18=25

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