Divide ₹47 among A,B and C so that A may have ₹10 more than B and B has ₹8 more than C.
Please show calculation.
Answers
Answered by
3
total money = 47
let the money C has = x
money B has = x+8
money A has = x+8+10 =x+18
so we have an equation
x+x+x+8+18=47
3x+26=47
3x= 21
x= 7
x=7
x+8=7+8=15
x+18=7+18=25
let the money C has = x
money B has = x+8
money A has = x+8+10 =x+18
so we have an equation
x+x+x+8+18=47
3x+26=47
3x= 21
x= 7
x=7
x+8=7+8=15
x+18=7+18=25
AnanyaSrivastava999:
so I can't answer it even
Similar questions