Question

Divide 47 between A,B,C. so that A may have Rs 10 more than B and B and, more than C​

Answer 1

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let c=x

so,47=a+b+c

47=x+{x+8}+(x+8)+10

because it is given that c+8=b and b+10 =a

47=3x+26

3x=21

x=7

so,c=7

b=7+8=15

a=15+10=25

Answer 2

$\huge \tt \pink {answer}$

let c=x

so,47=a+b+c

47=x+{x+8}+(x+8)+10

because it is given that c+8=b and b+10 =a

47=3x+26

3x=21

x=7

so,c=7

b=7+8=15

a=15+10=25