Math, asked by ashutosh22sony, 10 months ago

divide 48 (2y⁴ – 36y² + 162) by 4 (y - 3)²​

Answers

Answered by mysticd
25

Answer:

 \frac{48(2y^{4}-36y^{2}+162)}{4(y-3)^{2}}=24(y+3)^{2}

Step-by-step explanation:

 \frac{48(2y^{4}-36y^{2}+162)}{4(y-3)^{2}}

=\frac{48\times 2(y^{4}-18y^{2}+81)}{4(y-3)^{2}}

=\frac{96[(y^{2})^{2}-2\times y^{2}\times 9+9^{2}]}{4(y-3)^{2}}

=\frac{24(y^{2}-9)^{2}}{(y-3)^{2}}

=\frac{24(y^{2}-3^{2})^{2}}{(y-3)^{2}}

=\frac{24[(y+3)(y-3)]^{2}}{(y-3)^{2}}

=\frac{24(y+3)^{2}(y-3)^{2}}{(y-3)^{2}}

= 24(y+3)^{2}

Therefore,

 \frac{48(2y^{4}-36y^{2}+162)}{4(y-3)^{2}}=24(y+3)^{2}

•••♪

Answered by pragnya1842
5

Answer:

hope \: it \: helps \:

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