Question

divide 489 into two parts such that the first part is 9 more than twice the second part​

Answer 1

second part=x

first part =2x + 9

(2x +9) + x = 489

2x + 9 + x = 489

3x+9 = 489

3x= 489-9

3x= 480

x=480÷3

x=160

therefore second part is 160 and first part is 2×160+9=329

Answer 2

Answer:

I hope it will be helpful