divide 489into two parts such that the first part is 9 more than twice the second part
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Answered by
19
First part be =x
Second part =(489-x)
X+9=2(489-x)
=x+9=978-2x
=x+2x=978-9
=3x=969
x=969\3
x=323
Now first part =x
323
Second part =(489-x)
489-323
=166
Second part =(489-x)
X+9=2(489-x)
=x+9=978-2x
=x+2x=978-9
=3x=969
x=969\3
x=323
Now first part =x
323
Second part =(489-x)
489-323
=166
shruti415:
how
i don't no because it is give in answer
then pls check ur question again
it is write
I mean to say that pls check ur question which you have written in
it is right or wrong
yes it is write
then I don't know but I think that it is right but should also check
yes i written in book i will ask to my teacher
Okk thank you
Answered by
10
Hey bro your answer is in attachment
Let this solution help more students
solved by pя¡ყคnรнu
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