Question

Divide:
48a$48a^3b^2c^4 by (-4a^2bc^2)$

Answer 1

Answer:

Factorise 4a

2

+b

2

+c

2

−4ab+2bc−4ca using identity

Easy

Solution

4a

2

+b

2

+c

2

−4ab+2bc−4ca

=(2a)

2

+(−b)

2

+(−c)

2

+2(2a)(−b)+2(−b)(−c)+2(2a)(−c)

We know that x

2

+y

2

+z

2

+2xy+2yz+2xz=(x+y+z)

2

Here, x=2a, y=−b and z=−c

So, 4a

2

+b

2

+c

2

−4ab+2bc−4ca

=(2a−b−c)

2

=(2a−b−c)(2a−b−c)

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Answer 2

Answer:

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