Question

Divide : 48x2(x4 – 3x3-18x2) by16x2(x-6)​

Answer 1

Answer:

$3x^2(x+3)$

Step-by-step explanation:

$\frac{48x^2(x^4-3x^3-18x^2)}{16x^2(x-6)} \\\\\frac{3(x^4-3x^3-18x^2)}{(x-6)} \\\\\frac{3x^2(x^2-3x-18)}{(x-6)} \\\\\frac{3x^2(x^2+3x-6x-18)}{(x-6)} \\\\\frac{3x^2[x(x+3)-6(x+3)]}{(x-6)} \\\\\frac{3x^2(x-6)(x+3)}{(x-6)} \\\\3x^2(x+3)}$