divide :
4a^2+12ab+9b^2-25c^2 by 2a+3b+5c
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4a^2+12ab+9b^2-25c^2 by 2a+3b+5c
=(2a)^2+2x2ax3b+(3b)^2-(5c)^2
=(2a+3b)^2-(5c)^2
=(2a+3b+5c)(2a+3b-5c)
=4a^2+12ab+9b^2-25c^2÷(2a+3b+5c)
=(2a+3b+5c)(2a+3b-5c)/(2a+3b+5c)
=2a+3b-5c.
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