Question

divide 4a2+23a+ 15 by a+5
$4a ^{2} + 23a + 15 \: by \: a + b$
​

Answer 1

Step-by-step explanation:

$\frac{4 {a}^{2} + 23a + 15}{a + 5}$

$\frac{4 {a}^{2} + 20a + 3a + 15 }{a + 5}$

$\frac{4a(a + 5) + 3(a + 5)}{a + 5}$

$\frac{(4a + 3)(a + 5)}{a + 5}$

$4a + 3$