Question

divide (4a²-9b²) by (2a+3b)​

Answer 1

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Answer 2

$\bf\large\underline\blue{Question:-}$

• Divide $4a^{2}-9b^{2}$ by $(2a+3b)$

$\bf\large\underline\blue{Solution:-}$

$\frac{4 {a}^{2} - 9 {b}^{2} }{2a + 3b}$

$= \frac{ {(2a)}^{2} - {(3b)}^{2} }{(2a + 3b)}$

$= \frac{ \cancel{(2a + 3b)}(2a - 3b)}{ \cancel{(2a + 3b)}}$

$= 2a - 3b$

$\bf\large\underline\blue{Answer:-}$

• Answer is $2a - 3b$