Question

divide (4m^2n + 9n^2m + 3mn) divided by 4mn​

Answer 1

hi mate,

solution:

(4m2n+9n2m+3mn)/4mn

Step 1 :

Equation at the end of step 1 :

((((4•(m^2))•n)+(3^2n^2•m))+3mn)

(———————————---------————•m)•n

4

Step 2 :

Equation at the end of step 2 :

(((2^2m^2•n)+3^2mn^2)+3mn)

(—————————-----——————•m)•n

4

Step 3 :

4m^2n + 9mn^2 + 3mn

Simplify —————————————————

4

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

4m^2n + 9mn^2 + 3mn

= mn • (4m + 9n + 3)

Equation at the end of step 4 :

mn • (4m + 9n + 3)

(———————————————— • m) • n

4

Step 5 :

Multiplying exponential expressions :

5.1 m^1 multiplied by m^1 = m^(1 + 1) = m^2

Equation at the end of step 5 :

m^2n • (4m + 9n + 3)

——————————————————— • n

4

Step 6 :

Multiplying exponential expressions :

6.1 n^1 multiplied by n^1 = n^(1 + 1) = n^2

Final result :

m^2n^2 • (4m + 9n + 3)

—————————————————

4

i hope it helps you.

Answer 2

Step-by-step explanation:

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