Math, asked by naiksusamamanjari198, 1 month ago

divide 4x2 - 6x + a, 2x -1​

Answers

Answered by shriraam02007
0

Answer:

quotient = 2x - 2  

remainder = 0

Step-by-step explanation:

4x^2 - 6x + a / 2x - 1  

value for a

= 4x^2 - 6x + a                     x = 1/2

= 4 ( 1/2)^2 - 6 *( 1/2) + a = 0

= 1 - 3 + a = 0

= -2 + a = 0

a = 2

now putting value for a and dividing

4x^2 - 6x + 2 / 2x - 1  

=  2x - 1  /   4x^2 - 6x + 2      ( 2x - 2  

        (-)       4x^2 - 2x

               ---------------------

                          - 4x + 2

        (-)                - 4x + 2

                      -----------------

                                0

                      --------------------

so , when we divide 4x^2 - 6x + 2 / 2x - 1   we get,

quotient = 2x - 2  

remainder = 0

pls mark me the brainliest , rate and say thanks

                                                 

Similar questions