divide 4x⁴+x³+2x²+1 by x+1
plz answer step by step
Answers
Step-by-step explanation:
Given:-
4X^4+X^3+2X^2+1
To find:-
Divide 4X^4+X^3+2X^2+1 by X+1 ?
Solution:-
Given expression :4X^4+X^3+2X^2+1
Divisor = X+1
X+1) 4X^4+X^3+2X^2+1 (4X^3-3X^2+5X
4X^4+4X^3
(-) (-)
___________________
0 - 3X^3+2X^2
- 3X^3 -3X^2
(+) (+)
____________________
0 + 5X^2 +1
5X^2+5X
(-) (-)
_______________________
-5X+1 - Remainder
________________________
Answer:-
Quotient = 4X^3-3X^2+5X
Remainder = -5X+1
Check:-
Division Rule :-
Dividend = Divisor×Quotient+Remainder
=> (X+1)(4X^3-3X^2+5X) +(-5X+1)
=> X(4X^3-3X^2+5X)+1(4X^3-3X^2+5X)-5X+1
=>4X^4-3X^3+5X^2+4X^3-3X^2+5X-5X+1
=> 4X^4+X^3+2X^2+1
=> Given expression.
Verified the given relations.
Used formulae:-
Division Rule :-
Dividend = Divisor×Quotient+Remainder