Question

divide : 4xy(x²+6x-16) ÷2y(x+8)​

Answer 1

Answer:

2x² - 4x is the answer

Answer 2

Answer:

2x(x-2)

Step-by-step explanation:

4xy(

$4xy(x {}^{2} + 6x - 16) \div 2y(x + 8) =$

$x {}^{2} + 6x - 16 = x {}^{2} + 8x - 2x -16$

$= > x(x + 8) - 2(x + 8)$

$= > (x + 8)(x - 2)$

$\frac{4xy(x + 8)(x - 2)}{2y(x + 8)}$

$= > 2x(x - 2)$

$= > 2x {}^{2} - 4x$