Math, asked by abhijith27y, 3 months ago

Divide (4y3 + 5y2 + 6y) by 2y.​

Answers

Answered by Anonymous
15

 \: \huge \mathfrak{Solution}

 => 4 {y}^{3} + 5 {y}^{2} + 6y \div 2y

 =>\frac{4 {y}^{3} }{2y} + \frac{5 {y}^{2} }{2y} +  \frac{6y}{2y}

 => 2 {y}^{2} +  \frac{5y}{2} + 3

Hope it helps you ✌️

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