Divide 50 into two parts so that sum of the reciprocal is 1/12 ?; Divide 50 into two parts so that sum of the reciprocal is 1/12 ?
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let x+y=50 assume eq (1)
1/x+1/y=1/12
after solving we will get xy=600
we know that (x+y)^2-(x-y) ^2=4*xy
put value of x+y and xy.
we will get( x-y) ^2=100 so x-y=10 eq(2)
solve 1 and 2 we will get x=30,y=20
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