Math, asked by zeenatansarirgp, 17 days ago

Divide 50 into two parts such that five times the first part is less than twice the second part. the answer is; 14, 36 find the solution.​

Answers

Answered by hanacute1
0

Answer:

Step-by-step explanation:Let the two parts be X and Y.

Now according to given conditions,

X+Y=50,———-(1)

And

1/X+1/Y=1/12————-(2)

Solving equation(2),we get,

(X+Y)/XY=1/12

50/XY=1/12—-(from eq(1))

XY=600———-(3)

Now solving eq(1) and (3) we get

X =30 and Y=20.

Therefore the two parts in which 50 is divided are 30 and 20.

Answered by sisirdasmmc
0

Answer:

Divide 50 into two parts such that five times the first part is less than twice the second part. the answer is; 14, 36 find the solution.

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