Question

Divide 50 into two parts such that the sum of their reciprocals is 1/12 The numbers are
(a) (24, 26)
(b) (28, 22)
(c) (27 ,23)
(d) (20, 30)​

Answer 1

Answer:

let one number be x

the other number will be 50-x

1/x + 1/(50-x)= 1/12

50-x+x = x(50-x)/12

600 = 50x-x^2

x^2-50x+600=0

x^2-30x-20x+600=0

x(x-30)-20(x-30)=0

(x-30)(x-20)=0

x= 20or 30 thenumbers are 20 and 30