Math, asked by sachin519, 1 year ago

divide 500 among A, B, C and D so that A and B together get thrice as much as C and D together, B gets four times of what C gets and C gets 1.5 times as much as D Now the value of what B gets is

Answers

Answered by Anonymous
44
b = 4 c
c = 1.5d
a+ b = 3( c + d )
a + 4c = 3( 1.5 d + d)
a + 4(1.5d)=7.5d
a+ 6d = 7.5 d
a=1.5d
so a + b + c + d = 500
1.5d + 4×1.5d + 1.5d +d =500
10d =500
d=50
so b =4c = 4×1.5 ×50 =60×5
b got 300
Answered by throwdolbeau
25

Answer:  

Share of B = Rs. 300

Step-by-step explanation:

Given that A and B together get thrice as much as C and D together

⇒ (A + B) = (C + D) = 3 : 1

Total money which is to be distributed = Rs 500

Share of (A + B) = 3/4 × 500 = Rs. 375

Share of (C + D) = 1/4 × 500 = Rs. 125

Now, C gets 1.5 times as much as D

⇒ C + D = 125

⇒ 1.5 D + D = 125

⇒ 2.5 D = 125

⇒ Share of D = Rs. 50

So, Share of C = 125 - 50  

                        = Rs. 75

Also, B gets four times of what C  gets

⇒ Share of B = 75 × 4

                       = Rs. 300

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