Math, asked by sayeem191620, 16 days ago

Divide 500 into two parts such that one third of the first part is more by 60 than one fifth of the second part.​

Answers

Answered by rachit00441
0

Answer:

can't understand the question

Answered by 14vs1010582
4

Answer:

Let the first part be x and the second part be y.

Hence, 1/3x = y-40

And, y= 1/3x + 40

Therefore, (1/3x + 40)+ x = 400

1/3x + x = 360

4/3x = 360

x = 360* 3/4

x = 270 ( first part )

y = 1/3x + 40 = 130

or

Let the first part be x and the second part be y.

Hence, 1/3x = y-40

y= 1/3x + 40  and

x+y =400

(1/3x + 40)+ x = 400

1/3x + x = 360

4/3x = 360

x = 360* 3/4

x = 270

y = 1/3x + 40 = 130

so two part of 400 are 270 and 130.

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