Question

Divide 51/11÷-18/16

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Answer 1

Given data: $\frac{51}{11}$÷$\frac{18}{16}$

To Find: The division of the number $\frac{51}{11}$÷$\frac{(-18)}{16}$

Solution:

Consider the given division, $\frac{51}{11}$÷$\frac{(-18)}{16}$

To simplify the given numbers, convert the division into multiplication.

$\frac{51}{11}$÷$\frac{(-18)}{16}$ $=\frac{51}{11}$×$\frac{16}{(-18)}$ , since when division is converted into multiplication, the second term will be changed to reciprocal.

Hence, the first term will remain same and the second term of the numerator will become denominator and vice versa.

Multiply the numerator and denominator,

$\frac{51}{11}$÷$\frac{(-18)}{16}$ $=\frac{51}{11}$×$\frac{16}{(-18)}$

$\frac{51}{11}$÷$\frac{(-18)}{16}$ $=\frac{816}{(-198)}$  

$\frac{51}{11}$÷$\frac{(-18)}{16}$$=\frac{136}{(-33)}$  

$\frac{51}{11}$÷$\frac{(-18)}{16}$$=-\frac{136}{33}$ or $-4.12$

Therefore, the division of  $\frac{51}{11}$÷$\frac{(-18)}{16}=-\frac{136}{33}$ or $-4.12$

Answer 2

$\dfrac{51}{11} \div \dfrac{-18}{16} = -\dfrac{136}{33}$

Given:

• $\dfrac{51}{11} \div \dfrac{-18}{16}$

To Find:

• Simplify

Solution:

$\dfrac{51}{11} \div \dfrac{-18}{16}$

Step 1:

To divide by a fraction, multiply by the reciprocal of that fraction

$\dfrac{51}{11} \times \dfrac{16}{-18}$

Step 2:

51 and 18 has common factor 3 Hence divide both by 3

$\dfrac{17}{11} \times \dfrac{16}{-6}$

Step 3:

16 and 6 has common factor 2 Hence divide both by 2

$\dfrac{17}{11} \times \dfrac{8}{-3}$

Step 4:

Multiply 17 by 8 and 11 by -3

$\dfrac{136}{-33}$

Step 5:

Taking -ve sign out

$-\dfrac{136}{33}$

$\dfrac{51}{11} \div \dfrac{-18}{16} = -\dfrac{136}{33}$