Question

divide 51 into two numbers such that when the larger is divided by the smaller the quotient is 2 and the remainder is 6​

Answer 1

Answer:

it is only possible for 17 and 3

Step-by-step explanation:

Answer 2

Answer:

36 and 15

Step-by-step explanation:

Let the two parts be x and 51-x

Let the larger part be x

Given that, when x is divided by 51-x the quotient is 2 and remainder is 6

We know the division algorithm

Dividend = (divisor x quotient) + remainder

Here, Dividend = x, divisor = 51-x, quotient =2 and remainder = 6

Thus,

x = 2(51-x) +6

or x= 102 -2x +6

or 3x =108

or x =36

Thus the two parts are 36 and 15