Question

divide 51 into two parts whose product is 608

Answer 1

Answer:

Let parts are

• x

• (51 - x)

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Their product = 608

(x)×(51 - x) =608

51x - x² = 608

x² - 51x + 608=0

Then,

a = 1

b = -51

c= 608

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Quadratic equation = [-b±√d]/(2a)

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d = discriminant =b²-4ac

=> (-51)²- 4(1)(608)

=> 2601 - 2432

=> 169

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Quadratic equation = [-(-51)±√169]/2

=> [51±13]/2

Taking +ve,

• x = (51+13)/2 = 64/2 = 32

Taking -ve,

• x = (51-13)/2 = 38/2 = 19

Then, we get,

• First part = x = 32 [taking 32]

Other part = 51 - 32= 19

• First part = x = 19 [taking 32]

Other part = 51-x = 51-19=32

And, mainly we get that the numbers are 19 and 32