Question

divide 51into two parts whose products is 608​

Answer 1

$\huge \mathfrak \pink{hello \: mate}$

Let the two parts be x and 51-x

Now,

x(51-x)=608

51x-x²=608

x²-51x+608=0

x²-19x-32x+608=0

x(x-19)-32(x-19)=0

(x-19)(x-32)=0

Hence the two parts are

19 and 32

Answer 2

Answer:32 and 19

Step-by-step explanation:

Let a+b=51...... equation(1) ; ab=608

(a+b)² = (a-b)² +4ab = 51x51

> (a-b)² = 2601-4ab= 169

> a-b = 13........ equation (2)

adding equation 1 and 2

we get 2a= 64

> a= 32

> b=51-32 = 19