Question

divide 534 into 3 parts such that the second part will be 32 less than twice the first and the third will be 18 more than the first

Answer 1

Answer:

let the 1st part be x

so, the second part will be 2x - 32

and the third part will be x + 18

now summing them up

x + 2x - 32 + x + 18 = 534

=> 4x = 548

=> x = 137

=> 2x - 32 = 242

=> x + 18 = 155

PLEASE MARK IT AS THE BRAINLIEST!!!!!♥️

Answer 2

Step-by-step explanation:

Given:

• Total sum is 534
• Second part is 32 less than twice the first
• Third part is 18 more than the first part

To Find:

• Measure of all parts

Solution: Let the first part be x

A/q

• Second part = 2x – 32
• Third part = x + 18

★ If we add First, Second and Third part then we will get total sum i.e 534 ★

$\small\implies{\sf }$ x + ( 2x – 32 ) + ( x + 18 ) = 534

$\small\implies{\sf }$ x + 2x – 32 + x + 18 = 534

$\small\implies{\sf }$ x + 2x + x – 32 + 18 = 534 [ Add all like terms together ]

$\small\implies{\sf }$ 4x – 14 = 534

$\small\implies{\sf }$ 4x = 534 + 14

$\small\implies{\sf }$ 4x = 548

$\small\implies{\sf }$ 548/4 = 137

Hence, Value of x ( First part ) is 137

∴ Second Part = 2x – 32 = 2(137) – 32

$\small\implies{\sf }$ 274 – 32

$\small\implies{\sf }$ 242

∴ Third Part = x + 18

$\small\implies{\sf }$ 137 + 18

$\small\implies{\sf }$ 155

_______________________

★ Check ★

• Adding all parts together •

→ 137 + 242 + 155 = 534

→ 534 = 534

Hence, LHS = RHS