Question

Divide 534 into three parts such that the second part will be 32 less than twice the first , and the third will be 18 more than the first.
Plz give me solution....

Answer 1

Let the first part be x
Then second part = 2x-32
Third part = x+18
Their sum = 534
x+2x-32+x+18 = 534
4x-14 = 534
4x = 534+14
4x = 548
x = 548/4
x = 137

First part = 137
Second part = 2(137)-32
= 274-32 = 242
Third part = 137+18 = 155

Answer 2

Answer:

First part = 137

second part = 242

third part = 155

Given:

Divide 534 into three parts such that the second part will be 32 less than twice the first , and the third will be 18 more than the first.

To find:

Find the parts.

Step-by-step explanation:

Hint:

The addition of all parts must be equal to 534.

Let us consider the first part be x.

It is given that,

→ the second part will be 32 less than twice the first

so, the second part will be

⇒ 2x - 32.

→ the third will be 18 more than the first.

so, the third part will be

⇒ x + 18

Now, add three parts:

⇒ (x) + (2x - 32) + (x + 18)

⇒ 4x - 14.

This must be equal to 534

∴ 4x - 14 = 534

⇒ 4x = 534 + 14

⇒ 4x = 548

⇒ x = 548/4

⇒ x = 137

Hence,

the part is x = 137

second part = 2x - 32 = 2(137) - 32 = 274 - 32 = 242

third part = x + 18 = 137 + 18 = 155

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