Question

divide 534 into three parts such that the second part will be 32 less than twice the first ,and the third will be 18 more than the first

Answer 1

First no. = x
Second no. = 2(first no.) - 32 = 2(x) - 32 = 2x - 32
Third no. = x + 18
First no. + Second no. + Third no. = 534
x + 2x - 32 + x + 18 = 534
4x - 14 = 534
4x = 534 + 14
4x = 548
x = 548/4
x = 137
First no. = x = 137
Second no. = 2x - 32 = 2 (137) - 32 = 274 - 32 = 242
Third no. = x + 18 = 137 + 18 = 155
Therefore the numbers are 137,242,155

Answer 2

$Please \: Mark \: Me \: As \: BRAINLIEST. \\ .................................................. \\ Also \: Don't \: Forgot \: to \: Follow \: me. \\ .............. \\ As \: we \: know \: about \: Equations. \\ So, \\ Hello \: Guys, \\ ................ \\ Answer \: is$
$Let \: first \: no. \: be \: x. \\ \: \: \: \: Second \: no. = 2 \times x - 32 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2x - 32 \\ \: \: \: \: \: \: \: Third \: no. = x + 18 \\ ATQ, \\ x + 2x - 32 + x + 18 = 534 \\ 4x - 14 = 534 \\ 4x = 534 + 14 \\ 4x = 548 \\ x = \frac{548}{4} \\ x = 137 \\ \\ First \: no. = 137 \\ Second \: no. = 137 \times 2 - 32 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 274 - 32 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 242 \\ Third \: no. = 137 + 18 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 155$