Question

Divide 534 into three parts such that the second part will be 32 less than twice the first, and the third will be 18 more than the first

Answer 1

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here is the solution ❤️

⏺️let the first part be 'x'

⏺️ second part be 2x - 32

⏺️& third part be x + 18

ACCORDING TO QUESTION.

==> x + (2x - 32) +x + 18 = 534

==> 3x -32 + x + 18 = 534

==> 4x -32 + 18 = 534

==> 4x - 14 = 534

==> 4x = 534 + 14

==> 4x = 548

==>x = 548/4

==>x = 137

SO,

the first number (x) is 137

second number (2x-3) is 242

and the third number (x + 18 ) is 155

VERIFY ✅✅

==>137 + 242 + 155

==> 534

Answer 2

$\huge \underline\mathfrak{solution}$

$<b>$
➡Let the first part be x

Then second part = 2x-32

Third part = x+18

Their sum = 534

x+2x-32+x+18 = 534

4x-14 = 534

4x = 534+14

4x = 548

x = 548/4

x = 137

First part = 137

Second part = 2(137)-32

= 274-32 = 242

Third part = 137+18 = 155

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