Math, asked by venkatsathvikkumarg, 7 months ago

divide 54 is in four parts in ap such that the ratio of product of their extrmes (1st and 4th) to the product of meas (2nd and 3rd in 5:6

Answers

Answered by ketaki1976
1

Step-by-step explanation:

Given:

↬ 56 is divided into four parts which form an A.P.

↬ Ratio of the product of extremes of given A.P. to the product of their means is 5:6

To Find:

All the parts of 56

Things to know before solving question

(a+b)(a-b)= a² -b²

Solution:

Let the four parts be a-3d, a-d, a+d, a+3d such that they are in A.P.

Now,

Sum of all parts= 56

⇒ a-3d+a-d+a+d+a+3d= 56

⇒ 4a= 56

⇒ a= 14

Now,

According to the question,

\sf{\dfrac{Product\:of\:extremes\:of\:A.P.}{Product\:of\:means\:of\:A.P.}=\dfrac{5}{6}}

ProductofmeansofA.P.

ProductofextremesofA.P.

=

6

5

i.e. \sf{\dfrac{Product\:of\:first\:and\:fourth\:terms\:of\:A.P.}{Product\:of\:second\:and\:third\:terms\:of\:A.P.}=\dfrac{5}{6}}

ProductofsecondandthirdtermsofA.P.

ProductoffirstandfourthtermsofA.P.

=

6

5

\longrightarrow\sf{\dfrac{(a-3d)(a+3d)}{(a-d)(a+d)}=\dfrac{5}{6}}⟶

(a−d)(a+d)

(a−3d)(a+3d)

=

6

5

\longrightarrow\sf{\dfrac{a^{2}-(3d)^{2}}{a^{2}-d^{2}}=\dfrac{5}{6}}⟶

a

2

−d

2

a

2

−(3d)

2

=

6

5

\longrightarrow\sf{\dfrac{a^{2}-9d^{2}}{a^{2}-d^{2}}=\dfrac{5}{6}}⟶

a

2

−d

2

a

2

−9d

2

=

6

5

\longrightarrow\sf{6(a^{2}-9d^{2})=5(a^{2}-d^{2})}⟶6(a

2

−9d

2

)=5(a

2

−d

2

)

\longrightarrow\sf{6a^{2}-54d^{2}=5a^{2}-5d^{2}}⟶6a

2

−54d

2

=5a

2

−5d

2

\longrightarrow\sf{6a^{2}-5a^{2}=54d^{2}-5d^{2}}⟶6a

2

−5a

2

=54d

2

−5d

2

\longrightarrow\sf{a^{2}=49d^{2}}⟶a

2

=49d

2

\longrightarrow\sf{49d^{2}=a^{2}}⟶49d

2

=a

2

On putting value of a in above equation, we get

\longrightarrow\sf{49d^{2}=14^{2}}⟶49d

2

=14

2

\longrightarrow\sf{49d^{2}=196}⟶49d

2

=196

\longrightarrow\sf{d^{2}=\dfrac{\cancel{196}}{\cancel{49}}}⟶d

2

=

49

196

\longrightarrow\sf{d^{2}=2}⟶d

2

=2

\longrightarrow\sf{d=\pm2}⟶d=±2

Now,

Case-1 ,when d=2

First part= a-3d= 14-3(2)= 8

Second part= a-d= 14-2= 12

Third part= a+d= 14+2= 16

Fourth part= a+3d= 14+3(2)= 20

Case-2 ,when d= -2

First part= a-3d= 14-3(-2)= 20

Second part= a-d= 14-(-2)= 16

Third part= a+d= 14+(-2)= 12

Fourth part= a+3d= 14+3(-2)= 8

Hence, all four parts are 8, 12, 16 and 20

Answered by Anonymous
1

Answer:

8,12,16,20

here is ur answer ⌐╦╦═─

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