Divide 543 into three parts such that the second part will be 32 less than twice the first and the third will be 18 more than the first
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Answered by
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Answer:
First part = x
Second part = 2x - 32
Third part = 18 + x
x + (2x - 32) + (18 + x) = 534
4x -14 = 534
4x = 548
x = 137
First part = 137
Second part = 242
Third part = 155
Total 534.
Hope this helps.
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Answered by
2
Answer:
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