Math, asked by masuma23, 5 months ago

Divide 543 into three parts such that the second part will be 32 less than twice the first and the third will be 18 more than the first​

Answers

Answered by st6531779
2

Answer:

First part = x

Second part = 2x - 32

Third part = 18 + x

x + (2x - 32) + (18 + x) = 534

4x -14 = 534

4x = 548

x = 137

First part = 137

Second part = 242

Third part = 155

Total 534.

Hope this helps.

:-)

Answered by khushi56336
2

Answer:

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