Question

divide 56 in 4 parts in AP such that the ratio of the product of their first and forth to the product of second and third then find the ratio​

Answer 1

Answer:

Let the four parts that are in AP be a-3d,a+d, a+3d

a-3d+a-d +a+d+a+3d=36

4a=56

a=14

ATQ

(a-3d)(a+3d)=5÷ ( a-d) (a+d)=6

a^2-9d^2÷a^2-d^2=5÷6

6(196-9d^2)=5(196-d^2)

1176-54d^2=980-5d^2

49d^2=196

d=+-2

four part 8,12 d=2 and 20,16,12if d=-2