Question

divide 56 in four parts in A.P such that the ratio of the product of their extremes (1st and 4th) to the product of means (2nd and 3rd) is 5:6. please answer it, i will mark as brianliest and also will start following the one who answers it thank-you☺​

Answer 1

4 no =a-3d,a-d,a+d,a+3d

sum , 4a=56

a=14

(a-3d)(a+3d)/(a-d)(a+d)=5:6

6(a²-9d²)=5(a²-d²)

a²=54d² - 5d²

14² =49d²

d²=14² /7²

d=±14/7=±2

for d=2,

a-3d=14-6=8

a-d=14-2=12

a+d=14+2=16

a+3d=14+6=20

Numbers are 8, 12, 16, 20

Hope this helps!

Mark as the best answer..

Answer 2

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