Question

Divide 56 in four parts in A.P. such that the ratio of the product of their extremes (1 and 4th) to the
product of middle (2nd and 3rd) is 5:6​

Answer 1

Answer:

Numbers are 8,12,16,20.​

Step-by-step explanation:

Let the four parts be a−3d,a−d,a+d,a+3d

Sum, 4a=56

a=14

(a−d)(a+d)/(a−3d)(a+3d) = 5/6

6(a2−9d2)=5(a2−d2)

a2=49d2

d=±2

For d=2,

Numbers are 8,12,16,20.​