Question

Divide 56 in four parts in AP such that the ratio of the product of 1st and the last term to
the product of the two middle terms is 5:6



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Answer 1

Answer:

Let the four parts be a−3d,a−d,a+d,a+3d

Sum, 4a=56

a=14

(a−d)(a+d)

(a−3d)(a+3d)

=

6

5

6(a

2

−9d

2

)=5(a

2

−d

2

)

a

2

=49d

2

d=±2

For d=2,

Numbers are 8,12,16,20.

Answer 2

Answer:

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