Question

Divide 56 in four parts in AP such that the ratio of the product of the extremes to the product of their means is 5:6

Answer 1

Answer:

Step-by-step explanation:

Four parts are

a-2d, a-d,a+d, a+2d

a-d+a-2d+a+d+a+2d =56

a=14

A.T.Q

a-3d×a+3d/a-d×a+d =5/6

Put value of a

196-9d^2/ 196-d^2= 5/6

d= 2

Four parts are-.10,12,16,18