Divide 56 in four parts in AP such that the ratio of the product of the extremes to the product of their means is 5:6
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Step-by-step explanation:
Four parts are
a-2d, a-d,a+d, a+2d
a-d+a-2d+a+d+a+2d =56
a=14
A.T.Q
a-3d×a+3d/a-d×a+d =5/6
Put value of a
196-9d^2/ 196-d^2= 5/6
d= 2
Four parts are-.10,12,16,18
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