Question

Divide 56 in to two parts such that three times the first part exceeds one third of the second by 48 .The parts are.

Answer 1

hi there,
let the first part be x
there fore according to the question 3x-(56-x)/3=48
(9x-56+x)/3=48
10x-56=144
10x=200
x=200/1=20
so the first part is 20 and the second part is 56-20=36
i hope this helps u...

Answer 2

let first part be x
then the second part be............
According to the question,
                                3x-(56-x)/3=48
                                     (9x-56+x)/3=48
                                      10x-56=144
                                            10x=144+56
                                                x=200/10
                                                x=20
therefore, second number will be = 56-x
                                                       =56-20
                                                       =36