Question

Divide 56 into two parts, so that thrice of the first part becomes 48 more than one third of the second part

Answer 1

Divided 56 into two parts such that three times the first part exceed one third of second by 48. 
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Part one:: x
Part two:: 56-x
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Equation:
3(56-x)-(1/3)x = 48
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168 - 3x - (1/3)x = 48
-10/3 x = - 120
(1/3)x = 12
x = 36
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56-x = 20
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Cheers,
Stan H.
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The parts are 
a. 25, 31 
b.20,36 
c.24, 32