Math, asked by khezir6095, 1 year ago

Divide 56 into two parts such that three times the first part exceed one third of the second by 48 .the parts are

Answers

Answered by foley
10
let one part be .x
other part will be 56-x
3x-((56-x)/3)=48
x =20
56-x=36
Answered by suraniparvin
4
See the attach file for ur ans
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