Question

divide 56 into two parts such that three times the first part exceeds one third of the second by 48

Answer 1

Answer:

Step-by-step explanation:

let one part be x

so the other part is 56-x

ATQ,

3x-(56-x/3)=48

(9x-56+x)/3=48

10x-56=144

10x=200

x=20

so one part is 20 and the other part is 36.

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