Question

Divide 560 chocolates between Arun Ashok in the ratio 9:8
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Answer 1

Answer:

Divide 560 chocolates between Arun Ashok in the ratio 9:8

Step-by-step explanation:

\begin{gathered}number \:of \: chocolates \: arun \: will \: get \: \\ = \frac{7}{7 + 4} \times 66 \\ = \frac{7 \times 66}{11} = 7 \times 6 = 42 \\ \\ number \:of \: chocolates \: vikas \: will \: get \: \\ = \frac{4}{11} \times 66 = 4 \times 6 = 24\end{gathered}

numberofchocolatesarunwillget

=

7+4

7

×66

=

11

7×66

=7×6=42

numberofchocolatesvikaswillget

=

11

4

×66=4×6=24

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Answer 2

Answer:

Given, the ratio of 3:2

whose two parts are 3 and 2

the sum of two parts 3+2=5

if there are 5 pens sheela will get 3 and sangeeta will get 2

therefore, if we have 20pens

sheela = $\frac{3}{5}\times20=12$

sangeeta= $\frac{2}{5}\times20=8$

hence, out of 20 pens sangeeta gets 8 and sheela gets 12. ,SangeetaSheela