divide 57 into two parts whose product is 782
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Answer:
23 and 34
Step-by-step explanation:
Let the two numbers be x and y.
Then,
x+y=57
or,x=57-y
xy=782
Substituting x,
(57-y)y=782
or,57y-y^2=782
or,-y^2+57y-782=0
or,(-1)(y^2-57y+782)=0
or,y^2-57y+782=0
or,y^2-23y-34y+782=0
or,y(y-23)-34(y-23)=0
or,(y-34)(y-23)=0
or,y-34=0. or,y-23=0
or,y=34. or,y=23
or,x=57-34. or,x=57-23
or, x=23. or,x=34
Hence the 2 numbers are 23 and 34
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