Math, asked by as4523133, 3 days ago

divide 57 into two parts whose product is 782

Answers

Answered by banerjeesoham27
1

Answer:

23 and 34

Step-by-step explanation:

Let the two numbers be x and y.

Then,

x+y=57

or,x=57-y

xy=782

Substituting x,

(57-y)y=782

or,57y-y^2=782

or,-y^2+57y-782=0

or,(-1)(y^2-57y+782)=0

or,y^2-57y+782=0

or,y^2-23y-34y+782=0

or,y(y-23)-34(y-23)=0

or,(y-34)(y-23)=0

or,y-34=0. or,y-23=0

or,y=34. or,y=23

or,x=57-34. or,x=57-23

or, x=23. or,x=34

Hence the 2 numbers are 23 and 34

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