Question

divide 585 into three parts such that the second part is 10 more twice the first, and the third is 75 more than fiest. Find the numbers. ​

Answer 1

Answer:

125,260 and 200 are the numbers

Let the first number be x

then, second will be 2x+10

and third will be x+75

ATQ

(x)+(2x+10)+(x+75) = 585

x+2x+x+10+75 = 585

4x + 85 = 585

4x = 585-85

4x = 500

x = 500/4

x= 125 ( first number)

second number = 2(125)+10

=250+10

=260

third number will be = (125)+75

=200

So, l have answered your question hope it helps you

Answer 2

Answer:

1st=125

2nd=260

3rd=200

Step-by-step explanation:

let,

1st number=x

2and number=10+2x

3rd number=75+x

from the question

x+(10+2x)+(75+x) = 585

4x+85 =585

4x =585-85

x =500/4

x =125

therefore,

1st number = x =125

2nd number = 10 + 2x =260

3rd number = 75+x=200