Divide (5x³-12x² + 12x + 13) by (x² − 3x+4)
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f(x)=12x3−13x2−5x+7
When f(x) is divided by (3x+2) the remainder is f(−32). Now,
f(−32)=12(−32)3−13(−32)2−5(−32)+7
=12(−278)−13(94)+310+7
−932−952+310+7=99=1
∴ The remainder is 1.
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