Question

Divide 60 into 3 parts such that the third part is 10 more than the second and the second part is 10 more than the first.​

Answer 1

10 + 20 + 30

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Answer 2

ATQ

Let

Second part = x

Third part = x + 10

First part= x-10


Adding

X + (X+10) + (X-10) = 60

3X = 60

X=20

First part = X-10 = 10

Second part = X = 20

Third part = X+10 = 30